My Pots, in the Winter Snow

The big snow we are getting today called me to action, grabbing the camera kind of action.

Julie likes to refer to the pot on the left as the flying saucer.  Add on the snow and I now believe it looks somewhat alien in appearance.

I’d like to add that the flying saucer brings great visual interest to the landscape in the winter time scene. A simple vertical element reaching up through all that white.

From flying saucer

Great Peril to Myself

So off I went struggling deep into the massive snow,  3.0 ft away from the back door into several inches of snow to get these images for you. It was quite the expedition, but don’t worry I’m okay.

Braving the elements I was able to get several award winning shots of the pots, woodlands, and flora still sticking up through gigantic snowbanks.

From pots, pots, and more pots

To my Left

I forced myself to step out another foot or so and a couple of steps to my left to capture the spirit of the pots as they continued to fill with snow.

In the background are the pots that held tropicals this past season . . . including a very nice banana tree. The red trunk with the large red/green leaves played very well against the aging cedar fence.

I also like how the ‘grape vine‘ on the trellis is capturing snow and creating that scene for us to admire.It’s a small vignette but one that(at a glance) makes it appear that snow is somehow clinging to the fence.

My office window is just to the left of that trellis and it’s a nice view out the window. The fence, the trellis and the woodlands beyond . . . a view that never tires us.

From AH_fall landscape 1108

The Collage

Finally . . . a stunning collage of what’s happening across the back yard on this winter day as the snow continues and the temperatures drop into single digits, I appreciate the winter view we have created to compliment the woodlands backdrop.


One response to “My Pots, in the Winter Snow

  1. E=mc²/2
    2009 is the end of Einstein’s space-jail of time and Fraud symbol E=mc²
    Time is not a structure like space to allow space-to time-back to space jumping claimed by Physicists regardless of what physicists have to say about it because Physics is a business and not necessarily science or scientific and like every business it comes with fraud and fraud is Einstein’s space-time (x, y, z, it) continuum that led to fraud symbol E=mc² and yes I am saying that 109 years of Nobel prize winners physics and physicists are all wrong and space-time physics is based on scientific fraud. When “results” expected and “No” discovery, Physicists rigged Physics for grant money since the start of the industrial revolution. Physics today is at least 51 % fraud!
    r ——————>>Exp (ì w t) ———->> S=r Exp (ì wt) Nahhas’ Equation
    Orbit——–>> Orbit light sensing——>> Visual Orbit; Exp = Exponential
    Particle —->> light sensing of moving objects———— >> Wave
    Newton———>>light sensing———->> Quantum
    Quantum = Newton x Visual Effects
    Quantum – Newton = Relativistic = Optical Illusions
    E (Energy by definition) = mv²/2 = mc²/2; if v = c
    m = mass; v= speed; c= light speed; w= angular velocity; t= time
    S = r Exp (ì w t) = r [cos (wt) + ì sin (wt)] Visual effects
    P = visual velocity = change of visual location
    P = d S/d t = v Exp (ì w t) + ì w r Exp (ì w t)
    = (v + ì w r) Exp (ì w t) = v (1 + ì) Exp (ì w t) = visual speed; v = wr
    E (visual energy= what you see in lab) = m p²/2; replace v by p in E = mv²/2
    = m p²/2 = m v²/2 (1 + ì) ² Exp (2ì wt)
    = mv²/2 (2ì) [cosine (2wt) + ì sine (2wt)]
    =ì mv² [1 – 2 sine² (wt) + 2 ì sine (wt) cosine (wt)];v = speed; c = light speed
    wt = π/2
    E (visual) = ìmv² (1 – 2 + 0)
    E (visual) = -ì mc² ≡ mc² (absolute value;-ì = negative complex unit) If v = c
    w t = π/4
    E (visual) = imv² [1-1 +ỉ] =-mc²; v = c
    wt =-π/4+ỉln2/2; 2ỉ wt=-ỉπ/2 – ln2
    Exp (2i wt) = Exp [-ỉπ/2] Exp [ln(1/2)]=[-ỉ (1/2)]
    E (visual) = imv² (-ỉ/2) =1/2mc² v = c
    Conclusion: E = mc² is the visual Illusion of E = mc²/2 All rights reserved.
    PS: In case of E=mc² claims to be rest energy claims then
    E=1/2m (m v + m’ r) ² = (1/2m) (m’ r) ²; v = 0
    E = (1/2m) (mc) ²; m’ r =mc

    Yes, you’re right

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